powershell cmd script of out-zip.ps1

i have found this powershell script online and i would like to run this from a batchfile. Can anyone give me the correct syntax for this script.
And if possible make it possible to input multiple directories the script wil zip.

########################################################
# out-zip.ps1
#
# Usage:
#    To zip up some files:
#       ls c:source*.txt | out-zip c:targetarchive.zip $_
#
#    To zip up a folder:
#       gi c:source | out-zip c:targetarchive.zip $_
########################################################

$path = $args[0]
$files = $input

if (-not $path.EndsWith('.zip')) {$path += '.zip'} 

if (-not (test-path $path)) { 
  set-content $path ("PK" + [char]5 + [char]6 + ("$([char]0)" * 18)) 
} 

$ZipFile = (new-object -com shell.application).NameSpace($path) 
$files | foreach {$zipfile.CopyHere($_.fullname)}

So what I actually need is the cmd file that says this (preferably with extra folders)

gi c:source | out-zip c:targetarchive.zip $_

Thanks, Kim!

I had the same problem with only a 1kb zip file being created. I found that I had do include a -noexit in the command:
powershell.exe -noexit -Command “gi c:source | C:usersKimDpcumentsWindowsPowerShellout-zip.ps1 c:targetarchive.zip”

Granted, this seems to cause some other issues when trying to use this in a batch file because it leaves powershell open. There are some other solutions out there that I’m investigating that will either just wait for a set amount of time for the “zip” to complete or that actually compares the source files with the completed zip file before exiting.

I cleaned up the PowerShell script file for you:

<#
.SYNOPSIS
Zip up files and folders
.EXAMPLE
To zip up some files:
    ls c:source*.txt | out-zip.ps1 c:targetarchive.zip
.EXAMPLE
To zip up a folder:
    gi c:source | out-zip c:targetarchive.zip
#>

param(
    [parameter(Mandatory=$TRUE,ValueFromPipeline=$TRUE)] $files,
    [parameter(Mandatory=$TRUE,position=0)] [string] $path
)

if (-not $path.EndsWith('.zip')) {$path += '.zip'} 

if (-not (test-path $path)) { 
  set-content $path ("PK" + [char]5 + [char]6 + ("$([char]0)" * 18)) 
} 

$zipFile = (new-object -com shell.application).NameSpace([System.IO.Path]::GetFullPath($path)) 
$files | %{$zipfile.CopyHere($_.fullname)}

Assuming out-zip.ps1 is saved to C:usersKimDpcumentsWindowsPowerShellout-zip.ps1, below is the batch file you need.

@echo off
powershell.exe -Command "gi c:source | C:usersKimDpcumentsWindowsPowerShellout-zip.ps1 c:targetarchive.zip"